(a) Develop stack machine code equivalents of the following simple programs:
(1) void main () {
for (int i = 0; i <= 10; i++) write(i, "\n")
}
0 DSP 1
2 LDA 0
4 LDC 0
6 STO
7 LDA 0
9 LDV
10 LDC 10
12 CLE
13 BZE 32
15 LDA 0
17 LDV
18 PRNI
19 PRNS "\n"
21 LDA 0
23 LDA 0
25 LDV
26 LDC 1
28 ADD
29 STO
30 BRN 7
32 HALT
(2) void main() { // factorials
int n, f;
read(n);
write(n, "! =");
f = 1;
while (n > 0) {
f = f * n;
n = n - 1;
}
write(f);
}
0 DSP 2
2 LDA 0
4 INPI
5 LDA 0
7 LDV
8 PRNI
9 PRNS "! ="
11 LDA 1
13 LDC 1
15 STO
16 LDA 0
18 LDV
19 LDC 0
21 CGT
22 BZE 45
24 LDA 1
26 LDA 1
28 LDV
29 LDA 0
31 LDV
32 MUL
33 STO
34 LDA 0
36 LDA 0
38 LDV
39 LDC 1
41 SUB
42 STO
43 BRN 16
45 LDA 1
47 LDV
48 PRNI
49 HALT
(3) void main () { // simple array handling
int i = 1;
int[] list = new int[11];
list[0] = 5;
while (i <= 10) {
list[i] = 2 - list[i-1];
i++;
}
}
0 DSP 2
2 LDA 0
4 LDC 1
6 STO
7 LDA 1
9 LDC 11
11 ANEW
12 STO
13 LDA 1
15 LDV
16 LDC 0
18 LDXA
19 LDC 5
21 STO
22 LDA 0
24 LDV
25 LDC 10
27 CLE
28 BZE 57
30 LDA 1
32 LDV
33 LDA 0
35 LDV
36 LDXA
37 LDC 2
39 LDA 1
41 LDV
42 LDA 0
44 LDV
45 LDC 1
47 SUB
48 LDXA
49 LDV
50 SUB
51 STO
52 LDA 0
54 INC
55 BRN 22
57 HALT
(b) Consider the following general form of T diagram. Although it uses the letters A through I in the various arms of the Ts, one could draw the diagram with fewer letters. How?
---------------------------- ----------------------------
| | | |
| A ----------> B | | C -----------> D |
| | | |
--------- ---------------------------- ---------
| | | |
| E | F --------> G | H |
| | | |
-------------------- --------------------
| |
| I |
| |
------------
Because of the rule that the "input" is semantically the same as the "output"
it follows that we can draw this
---------------------------- ----------------------------
| | | |
| A ----------> B | | A -----------> B |
| | | |
--------- ---------------------------- ---------
| | | |
| F | F --------> G | G |
| | | |
-------------------- --------------------
| |
| I |
| |
------------